A train leaves the station at time = 0. Traveling at a constant speed, the train travels 330 kilometers in 3 hours. Answers parts a and b. A. Write a function that relates the distance traveled d to time t. The function that relates the distance traveled d to the time is.

The function that relates the distance traveled d to the time t is

f(t) = 110t, where d = f(t)

Step-by-step explanation:

From the question, we were told that the train is At a constant speed, the train travels 330 kilometers in 3 hours

We were told to write function that relates the distance traveled d to the time t, we can do this by writing a linear equation with those functions

Since we are told that the train travels 330 kilometers in 3 hours, then we can say the train travel (330/3) kilometers in 1 hour which means it travel 110 kilometers in 1 hour

Then d= 110teqn(1)

If if t = 0, then d = 0, as well since at t=0 the train is at the station

At t = 1 then d = 110.

From equation (1) d can be replaced by f(t) then we have

f(t) = 110teqn(2)

Now we replace d by f (t), because d = f t):

f(t) = 120t

Therefore, The function that relates the distance traveled d to the time is f(t) = 120t

3.how is solving radical equations different than solving linear equations?

step-by-step explanation:

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.