Let $p$ and $q$ be the two distinct solutions to the equation $$(x-3)(x+3) = 21x - 63.$$ If $p > q$, what is the value of $p - q$?

Given:

p and q are the two distinct solutions to the equation

To find:

The value of p-q if p>q.

Solution:

We have,

Using zero product property, we get

Here, 18>3, so p=18 and q=3.

Now,

Therefore, the value of p-q is 12.

hey there!

12 is twice as much as 6 because 6 goes into 12 2 times.

since the rabbit is twice as tall, we should multiply the weight of the first rabbit, 0.25, by 2.

0.25 x 2 = 0.5

therefore, the 12 inch chocolate rabbit weighs 0.5 lb, or half a pound.

hope this !

go and ask your mom to you