The school store sells markers for $0.25 each and pencils for 0.50 each. Anthony spent $ 5.50 to buy a total of 16 markers and pencils. How many markers did Anthony buy?

The answer to your question is Antony bought 5 pens

Step-by-step explanation:

pens = p = $0.35

pencils = n = $0.15

total amount = 12

total money spent = $2.80

Process

1.- Write equations

              p  +  n  = 12                 (l)

       0.35p  +  0.15n = 2.80      (ll)

2.- Solve the system of equations by elimination

Multiply equation l by - 0.35

        - 0.35p - 0.35n = -4.2

          0.35p + 0.15 n = 2.8

             0      - 0.2n = -1.4

Solve for n

                        n = -1.4 / -0.2

                        n = 7      He bought 7 pencils

3.- Find the value of p

             p + 7 = 12

             p = 12 - 7

             p = 5                He bought 5 pens

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

x/3-10=8

x/3=18

x=48