![y = \frac{7}{4}x +14](/tpl/images/0938/0474/25094.png)
Step-by-step explanation:
Given
![y = \frac{7}{4}x + 4](/tpl/images/0938/0474/33519.png)
Required
Determine the equation of line that passes through (-8,0) and parallel to ![y = \frac{7}{4}x + 4](/tpl/images/0938/0474/33519.png)
Parallel lines have the same slope.
In ![y = \frac{7}{4}x + 4](/tpl/images/0938/0474/33519.png)
The slope, m is
![m = \frac{7}{4}](/tpl/images/0938/0474/857d6.png)
because the general form of a linear equation is:
![y = mx + b](/tpl/images/0938/0474/dc5b0.png)
Where
![m = slope](/tpl/images/0938/0474/196f9.png)
So, by comparison:
![m = \frac{7}{4}](/tpl/images/0938/0474/857d6.png)
Next, is to determine the equation of line through (-8,0)
This is calculated using:
![y - y_1 = m(x - x_1)](/tpl/images/0938/0474/f1736.png)
Where
![m = \frac{7}{4}](/tpl/images/0938/0474/857d6.png)
![(x_1,y_1) = (-8,0)](/tpl/images/0938/0474/f0ce3.png)
So, we have:
![y - 0 = \frac{7}{4}(x -(-8))](/tpl/images/0938/0474/8222a.png)
![y - 0 = \frac{7}{4}(x +8)](/tpl/images/0938/0474/15551.png)
![y - 0 = \frac{7}{4}x +\frac{7}{4}*8](/tpl/images/0938/0474/cf383.png)
![y - 0 = \frac{7}{4}x +7*2](/tpl/images/0938/0474/6bf17.png)
![y - 0 = \frac{7}{4}x +14](/tpl/images/0938/0474/7ebc4.png)
![y = \frac{7}{4}x +14](/tpl/images/0938/0474/25094.png)