Fuseina has ¢40000 to invest. She decides to put part of the money in an account paying 4% interest and the reminder into stocks paying 6% interest . Her financial advisor tells her that the total annual income from these investments should be¢2040. How much should she invest at each rate?

The amounts invested in the account = ¢ 18000

and the amount invested in the stock = ¢40000-¢18000= ¢22000.

Step-by-step explanation:

Given that the account paying 4% interest and the stocks paying 6% interest.

Assuming she put ¢ x in the account, so

Income (interest) from the account = 4% of x = ¢ 0.04x...(i)

She has a total of ¢ 40000 to invest, so the remaining amount = ¢(40000-x).

As she put the remaining amount into stock, so

Income (interest) from the stock=6% of (40000-x)=¢(2400-0.06x)...(ii)

As total income from the investment is ¢ 2040, so on adding both the incomes from equations (i) and (ii), we have

So, the amount invested in the account = ¢ 18000

and the amount invested in the stock = ¢40000-¢18000= ¢22000.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

a c

step-by-step explanation: