A dog kennel boards dogs for $8 a day. The kennel will also groom a dog for $12. The DeVilles have $52 budgeted for caring for the dog while they are on vacation. How many days, d, can they put the dog in the kennel if they are going to have the dog groomed? Write an equation to model this situation and solve

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Step-by-step explanation:

From the question, we are informed that a dog kennel boards dogs for $8 a day, the kennel will also groom a dog for $12 and that DeVilles have $52 budgeted for caring for the dog while they are on vacation.

Let the number of days that they can put the dog in the kennel if they are going to have the dog groomed be represented by d.

Therefore,

8d + 12d ≥ 52

20d ≥ 52

d ≥ 52/20

d ≥ 2.6

Since DeVilles have $52 budgeted for caring for the dog, the number of days they can put the dog in the kernel will be 2 days.

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5