Because of a problem in the program, the timer in a video player did not begin counting until the video had been playing for several seconds. The player began counting at 000 seconds, even though the video had already played 190190190 frames. The video plays 252525 frames per second. How many frames had the video already played when the time was equal to -3\dfrac{2}{5}−3 5 2 minus, 3, start fraction, 2, divided by, 5, end fraction seconds?

105 frames

Step-by-step explanation:

Given that:

At 0 seconds, the video had already played 190 frames and there are 25 frames being played per second.

When the time is equal to , the number of frames that are already being played is:

= 17 × 5

= 85 frames.

But recall that, the frames had already played 190 frames at 0 seconds, then the number of frames that had already been played when the time is equal to is;

=(190 - 85) frames

= 105 frames

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it