THE PRESENT AGE OF A FATHER IS THREE TIMES THAN THAT OF HIS SON. FIVE YEARS AGO HE WAS FIVE TIMES AS OLD AS HIS SON. FIND THEIR PRESENT AGES. (STEP BY STEP PLZ) (HOPE U ENJOY IT)

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Step-by-step explanation:

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His son is 10 and his father is 30.

Step-by-step explanation:

Let the age of his son be x and his father's age be 3x.

5(x-5) = 3x-5

5x-25 = 3x-5

5x-3x = 25-5

2x = 20

x = 10

3x = 10 × 3

    = 30

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

step-by-step explanation: 4 cause 2+2=4