If an isosceles triangle has a fixed perimeter P, find the dimensions that maximize the area. Your answer should be in terms of P. Also show that this is indeed the maximum

all but the second one

step-by-step explanation:

cuz that one goes over 180

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d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

happy to

pls mark as brainliest

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23