(1, –1), (16, –4), (36, –6)
step-by-step explanation:
given that the function is
![f(x) =\sqrt{x}](/tex.php?f=f(x) =\sqrt{x})
this can also be written as
![y^{2} =x](/tex.php?f=y^{2} =x)
we have to graph this function and check which list of points lie on the graph
see attachment for graph:
we find that the points lying are (1,-1) (16,-4) and (36,-6)
since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.