The first number is 7 greater than a second number. Twice the first number is 4 more than three times the second. Find the two numbers.

Step-by-step explanation and

Setting up a system of equations would be the easiest method for this question. The first number will be x. The second number will be y. According to the question:

x+1=y

2x-4=5y

Since the first equation is already solved for y, you can plug the whole first equation in for y in the second equation, then solve for x.

2x-4=5(x+1) Distribute the 5

2x-4=5x+5 Subtract 5x from 2x

-3x-4=5 Subtract -4 from 5 (add 4 to 5)

-3x=9 Divide to get the x by itself

-3=x

Now that you have x solved for, you can plug it into the first equation (or second, if you prefer) to solve for y.

x+1=y

-3+1=y

-2=y

you already gave the answer

step-by-step explanation:

b segment jm is correct i think