A set of biology exam scores are normally distributed with a mean of 707070 points and a standard deviation of 666 points. Let XXX represent the score on a randomly selected exam from this set. Find P(64

Step-by-step explanation:

Given that, the mean, , and the standard deviation, , of normally distributed exam score are :

Let represent the score on a randomly selected exam from this set

The z-score, for the randomly selected exam score x:

For 64<x<76, the range of z-score is

Now, from the z-score table, the value for z=-1 is the probability for x<64.

As the value for z=-1 is 0.15866, so

P(x<64)=0.15866.

Similarly, the value for z=0.67 is 0.84134, so

P(x<76)=0.84134

So,

Hence,

it would be 6xy and -16xy.

1.true 2.false? ? i think. .

step-by-step explanation: