Dr. Cohn is testing how long it takes for a person's body to process a new medicine. She observes that the medicine is used by the body at a constant rate. For her latest test, Dr. Cohn starts with 15 milligrams of the medicine and notes that 12.6 milligrams remain unused after 1 hour. Which equation could Dr. Cohn use to solve for p, the percentage of the medicine that is used in 1 hour? A. p100=12.615 B. p100=2.415 C. p15=1002.4 D. p15=10012.6

the options were not copied correctly, option B could be correct but it is missing the division signs:

B. p / 100 = 2.4 / 15

the percentage of medicine used in 1 hour:

p / 100 = (15 - 12.6) / 15 = 2.4 / 15

p / 100 = 0.16

p = 0.16 x 100 = 16%

another option could be C but it would be missing the multiplication signs:

C. p x 15 = 100 x 2.4

p x 15 = 240

p = 240 / 15 = 16%

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2