Find the time it takes for $9,200 to double when invested at an annual interest rate of 10%, compoun continuously.
years
Find the time it takes for $920,000 to double when invested at an annual interest rate of 10%, compounded
continuously.
years

years = natural log (total / principal) / rate

years = natural log (18,400 / 9,200) / 10

years = natural log (2) / 10

years = 0.69314718056 / 10

years = 6.9314718056

and this would be the time for ANY amount of money to double.

Step-by-step explanation:

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

huh? im pretty sure it is in 199

step-by-step explanation: