PLEASE HELP ME Slowhan decides to play a very fun game. He starts off with his favorite
odd integer. For every turn, Slowhan will either add 1 or subtract 1 to his current number.
What is the probability that after 11 turns, the resulting number will be odd?

Answer is even on the 11th turn unless Slowhan is allowed to skip a turn.

Step-by-step explanation:

If you add or subtract every turn then every turn will always be the opposite of the last turn, so, it would be.

odd is 0

1 = even

2 = odd (You've seen here that every even numbers of turns how answer will be odd and when it is an odd number of turns it will be even)

3 = even

4 = odd

5 = even

6 = odd

7 = even

8 = odd

9 = even

10 = odd

11 = even