(c^2 - 6)(2c^2 + 3c - 1)=(c
Mathematics, 30.11.2020 01:30 phancharamachasm
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Your answer should be a polynomial in standard form.
(c^2 - 6)(2c^2 + 3c - 1)=(c
2
β6)(2c
2
+3cβ1)=left parenthesis, c, squared, minus, 6, right parenthesis, left parenthesis, 2, c, squared, plus, 3, c, minus, 1, right parenthesis, equals
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Expand.
Your answer should be a polynomial in standard form.
(c^2 - 6)(2c^2 + 3c - 1)=(c
(c^2 - 6)(2c^2 + 3c - 1)=(c
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