Factor: 3x4y3 – 48y3. Solution:

3x4y3– 48y3.

= 3y3(x4 – 16).

= 3y3[(x2)2 - 42].

= 3y3(x2 + 4)(x2 - 4).

= 3y3(x2 + 4)(x2 - 22).

= 3y3(x2 + 4)(x + 2)(x -2).
whats the answer?

1-for what value of x is line a parallel to line b 2-for what value of x is line a parallel to line b

What is the shape of the height and weight distribution

How does the graph of g(x)=⌊x⌋−3 differ from the graph of f(x)=⌊x⌋? the graph of g(x)=⌊x⌋−3 is the graph of f(x)=⌊x⌋ shifted right 3 units. the graph of g(x)=⌊x⌋−3 is the graph of f(x)=⌊x⌋ shifted up 3 units. the graph of g(x)=⌊x⌋−3 is the graph of f(x)=⌊x⌋ shifted down 3 units. the graph of g(x)=⌊x⌋−3 is the graph of f(x)=⌊x⌋ shifted left 3 units.