The given line passes through the points (0, ) and (2, 3). On a coordinate plane, a line goes through (0, negative 3) and (2, 3). A point is at (negative 1, negative 1).

What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point ()?

The given line passes through the points (0, ) and (2, 3).

On a coordinate plane, a line goes through (0, negative 3) and (2, 3). A point is at (negative 1, negative 1).

What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point ()?

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length