You roll a standard dice two times. What is the probability of getting a 6 on the first roll, then an even number on the second roll?

4 out of 12 chance.

Step-by-step explanation:

So its a 1 out of 6 chance for the first die, and a 3 out of 6 chance on the second die, so a 4 out of 12 chance of what was said to happen.

First die:

You want to roll a 6. There is one number on each side of the die, and there are 6 sides. Since you can only get a side with 6 once, you have a 1 out of 6 chance of landing a 6.

Second die:

You want to roll an even number. There are 3 even numbers on the die (2, 4, and 6), and there are 6 sides, with the other 3 sides being odd (1, 3, and 5). Since you can only get a side that is even three times, you have a 3 out of 6 chance of landing an even number (2, 4, or 6).

Combine these probabilities together, and you result in a 4 out of 12 chance of getting the requirements. The 4 comes from adding the chance of getting a 1 and 3 even numbers, and the 12 comes from adding the 2 6's (since two dices would result in 12 sides).

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15%

step-by-step explanation:

use the table and count the number of guesses that has two correct answers.

the following are two correct answers

10010, 01100, 11000

a total of 3 numbers having 2 correct guesses out of 20 questions.

probability of getting 2 correct guesses = the number of questions getting 2 correct answers / total number of questions.

= 3/20

to convert it into percent multiply by 100, we get

= 3/20 * 100

= 15%

the answer is 15%

you.

1e+27

step-by-step explanation: