Let a = ⟨5, –9⟩ and b = ⟨–3, 1⟩, and c = b – a. What is the magnitude and direction angle of c? |c| = 12.8; θ = 128.7°
|c| = 18.0; θ = 128.7°
|c| = 12.8; θ = 308.7°
|c| = 18.0; θ = 308.7°

A

Step-by-step explanation:

b i think

step-by-step explanation:

not really sure

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15