What is the equation of the line that passes through the point (-6,1) and has a slope of 1/6?

y - 1 = 1/6x + 1 <<< Point slope form

y = 1/6x + 2 <<< slope intercept form

Either one works unless the question specifies the form of the equation

Step-by-step explanation:

Point slope form: (y - y1) = m(x - x1)

Given: (-6,1) ; m = 1/6

(y - 1) = 1/6(x - (-6))

y - 1 = 1/6x + 1 <<< Point slope form

y = 1/6x + 2 <<< slope intercept form: y = mx + b

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: