The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) 5x/x^2 + 9. a. Find the time at which the concentration is a maximum. b. Find the maximum concentration.

Given :

The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by .

To Find :

Find the time at which the concentration is a maximum. b. Find the maximum concentration.

Solution :

For maximum value of x, K'(x) = 0.

Since, time cannot be negative, so ignoring x = -3 .

Putting value of x = 3, we get, K(3) = 15/( 9 + 9) = 5/6

Therefore, maximum value drug in bloodstream is 5/6 at time x = 3 units.

Hence, this is the required solution.

5x+2x=49

7x=49

x=7. 35 apples

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