1) Fairview and Abbots Rise are 5 in apart on a map that has a scale of 1 in : 18 mi. How far apart are the real cities? 2) A particular satellite is 12 ft wide. A model of it was built with a scale of 1 in :3 ft. How wide is the model? Please help me I have 4 more questoins

1) 90 mi

2) 4 inch

Step-by-step explanation:

1)

Given that the distance between Fairview and Abbots Rise on the map = 5 in

Scale of the map = 1 in: 18 mi

i.e. 1 inch on map is equivalent to an actual distance equal to 18 mi between the cities.

Given that the map has a distance of 5 inches.

Therefore, the actual distance between the cities = 5 18 = 90 mi

2) A particular satellite is 12 ft wide.

Model's scale = 1 in : 3 ft

i.e. 1 inch on map is equivalent to actual distance of 3 ft.

OR

3 ft of actual distance = 1 in on map

1 ft of actual distance = in on map

12 ft of actual distance =

whats the question?

step-by-step explanation:

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!