A pebble is dropped into a deep well and 3s later the sound of a splash is heard as the pebble reaches the bottom of the well. The speed of sound in air is about 340 m/s. How long will it take fir the pebble to hit the water? How long does is take for the sound to reach the observer? What is the depth of the well? (I need the equation)

0.11 seconds

Step-by-step explanation:

= Time taken by the pebble to hit the water

= Time taken by the sound to travel to the observer

= Time taken by the observer to listen to the splash after stone is thrown = 3 s

a = g = Acceleration due to gravity =

= Speed of sound = 340 m/s

The distance traveled by the pebble

Distance traveled by the sound

The distance traveled by the sound and the pebble is equal

Since the value of cannot be greater than 3.

So, time taken by the sound to reach the observer is 0.11 seconds.

Time taken by the pebble to hit the water is

Depth of the well is

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

answer: no

step-by-step explanation:

you are only given the cost not the amount of pounds.