A new food delivery robot on a college campus is doing test runs at a constant speed of 4 miles per hour. The average test run is 3 miles from the campus cafeteria but varies a distance of 1.5 miles more or less than that. If x is the number of hours the robot is performing a test run, the equation that can be used to find the minimum and maximum time (in hours) for a test run is . For each test run, the minimum time is hours and the maximum time is hours.

For each test run, the minimum time is 45 mins  or 3/4   hours

and the maximum time is 67.5 minutes or 1 hour 7.5 minutes.

Step-by-step explanation:

If x is the number of hours the robot is performing a test run, the equation that can be used to find the minimum and maximum time (in hours) for a test run is  15 mins for 1 mile

For 4 miles the time is 1 hour

For 1 miles the time will be 1/4 hour

For 3 miles the time will be 3/4 hours

and for 4.5 miles the time will be 4.5/4 hours

Now reversing

1 hour = 4miles

15 mins= 1 mile

45 mins = 3 miles

30 mins = 2 miles

67.5 min= 4.5 miles

For each test run, the minimum time is hours

the minimum distance is 3 miles and time taken is 45 mins

and the maximum time is hours.

The maximum distance is 3+ 1.5= 4.5 miles and time taken is 67.7 minutues or 1 hour 7.5 minutes.

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°

step-by-step explanation:

i'm pretty sure it would take 20 hours because it's half the men so you multiply the number of hours it takes by 2