Please need help with this question fast thank you so much.

Given the two points, [suppose their names are A and B] , A(-4,6) and B(4,2) you can find the gradient( M )of this line by the equation
y2-y1/ x2-x1 therefore
gradient(M)=2-6/4- (-4)
= 4/8 = 1/2

Use the formula equation of a line I.e
(Y=MX +C) and replace the x-coordinate and y-coordinate from ANY point, let’s say A(-4,6) where -4 is x and 6 is y, and dnt forget gradient(M)=1/2, like so:
Y=MX+C
6=1/2(-4) +C ————>(this is done to find C)
Therefore: C= 6 - 1/2(-4)
C=8<—

Finally to find equation of line in the form y=Mx+C , replace from the above answers:

Y=1/2x+8. Is the equation

The academic affairs council is the highest expert body processing academic affairs, as stipulated by the university statutes. specialist aaro häkkinen (educational policy) took part in the council’s meeting. the agenda of the meeting included bachelors’ feedback, the timing of pedagogical studies, the grant system for tuition fees, the standardisation of administrative practices for internships and the situation of foreign-language and multilingual master’s programmes.