09) The ratio of the number of jackfruit in baskets P, Q and R is 6:2:5. The total number of jackfruit
in basket Pis 48 more than the number of
jackfruit in basket Q. Calculate the total number
of jackfruits in the three baskets.
A 121 B 144 C 156 D 169

156 jackfruits

Step-by-step explanation:

Let there are 6x jackfruit in baseket P, 2x in basket Q and 5x in basket R.

The total number of jackfruit  in basket P is 48 more than the number of  jackfruit in basket Q. ATQ,

6x = 48 + 2x

Solving for x.

6x - 2x = 48

4x = 48

x = 12

Jackfruits in basket P = 6x = 6(12) = 72

Jackfruits in basket Q = 2x = 2(12) = 24

Jackfruits in basket R = 5x = 5(12) = 60

Total no of jackfruits = 72 + 24 + 60

= 156

So, there are 156 jackfruits in the three baskets.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol