3. Determine the amplitude (A), period (P) and phase shift (PS) of the function
f(x) = tan (2x + 1).
A = 1, p = ,PS = (2:0)
A = 1, P = 27, PS =
o
s = (2)
A = 1, p = 5, P = (1,0).
A = 1, P = 2.PS = (6, 1)

for f(x)=tan(2x+1)

Amplitude: None

Period: pi/2

phase Shift: -1/2(1/2 to the left)

understand that i don't know the answers

will someone answer his question

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.