Coordinate plane with squares WXYZ and W prime X prime Y prime Z prime and points A, B, C, and D at W negative 4 comma 3, X negative 2 comma 3, Y negative 4 comma 1, Z negative 2 comma 1, W prime negative 6 comma 1, X prime 0 comma 1, Y prime negative 6 comma negative 5, Z prime 0 comma negative 6, A negative 5 comma 4, B negative 3 comma 6, C negative 3 comma 4, and D negative 1 comma 4 Square WXYZ was dilated by a scale factor of 3 to create square W'X'Y'Z'. Which point is the center of dilation?

B
A
D
C

The correct option is;

C

Step-by-step explanation:

The scale factor by which WXYZ was dilated to create W'X'Y'Z' = 3

Therefore;

The distances of the points on W'X'Y'Z' from the center of dilation = 3 × The distances of the of the points of WXYZ from the center of dilation

The distances of the point W and X from the point C = 1 diagonal

The distances of the point W' and X' from the point C = 3 diagonals

Similarly;

The distances of the points Y and Z from the point C = 3 units down and 1 unit left and right respectively

Also, we have;

The distances of the points Y' and Z' from the point C = 3 × 3 = 9 units down and 3 × 1 = 3 unit left and right respectively

Which gives the center that dilates WXYZ to W'X'Y'Z' as the point C

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation: