Triangle J′K′L′ shown on the grid below is a dilation of triangle JKL using the origin as the center of dilation: Two triangles are drawn on a grid. First triangle has vertices J 8 and 12, K 4 and 8, L 12 and 6. Image triangle has vertices J prime 4 and 6, K prime 2 and 4, L prime 6 and 3.

Which scale factor was used to create triangle J′K′L′?

4
one quarter
2
one half

one half

Step-by-step explanation:

The vertices of triangle J′K′L′ are all half of their counterparts in Triangle J′K′L′ which means that the scale factor used was one-half.

First triangle has vertices J 8 and 12.

= 8/2 = 4

= 12/2 = 6

Image triangle has vertices J prime 4 and 6.

First triangle has vertices K 4 and 8

= 4/2 = 2

= 8 / 2 = 4

Image triangle has vertices K prime 2 and 4.

First triangle has vertices L 12 and 6

= 12/2 = 6

= 6/2 = 3

Image triangle has vertices L prime 6 and 3.

It is 1/4 I believe.

Step-by-step explanation:

a

explanation:

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2