1. A multi-cab starter motor has a current of 60.0 A and a voltage of 12 V. What is the resistance of the starter motor?
А
Given: Current (1)
Voltage (V)
Required: Resistance (9)
V
Formula:
R= voltage
curent
Solution:
V - IR

Resistance -
92, the resistance of the electric motor.

The resistance of the starter motor if a multi-cab starter motor has a current of 60.0 A and a voltage of 12V is 0.2 ohms

Based on the given question, for us to get the resistance of the starter motor, we will need to use Ohm's law.

According to the law, the current I passing through a conductor at constant temperature is directly proportional to the voltage "V". Mathematically;

V = IR

V is the voltage = 12V

I is the current = 60.0A

R is the resistance

Substitute the given parameters into the formula as shown:

12 = 60 R

R = 12/60

R = 1/5

R = 0/2

Hence the resistance of the starter motor if a multi-cab starter motor has a current of 60.0 A and a voltage of 12V is 0.2 ohms

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0.20 Ω

Step-by-step explanation:

From the question, we are informed that a multi-cab starter motor has a current of 60.0 A and a voltage of 12 V. The resistance of the starter motor will be calculated thus:

Current (I) = 60.0A

Voltage (V) = 12V

Resistance = Unknown

Since Voltage = Current × Resistance

Therefore, Resistance = Voltage / Current

= 12/60

= 0.20 Ω

The resistance of the motor is 0.20 Ω

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4