Suppose that the log-ons to a computer network follow a Poisson process with an average of three counts per minute. Required:
a. What is the mean time between counts?
b. What is the standard deviation between counts (in minutes)?
c. If it is an average of 3 counts per minute, find the value of x such that P(X < x) = 0.95

a. E(X) = 0.333 minutes

b.

c.  0.9986

Step-by-step explanation:

a.

To find the mean time between counts

Let X be the random variable that illustrates the time between the successive log-ons, then X is exponential with the rate log-ons per minute.

i.e.

E(X) = 0.333 minutes

b. Since X is attributed to an exponential distribution, The standard deviation between counts is:

c.

Given that;

The average number of count per minute = 3

The value of X such that P(X < x) = 0.95 can be calculated as;

-3x = ㏑ (0.05)

-3x = - 2.9957

x = -2.9957/ -3

x = 0.9986

The value of x = 0.9986

.5 lb

step-by-step explanation:

12 in / 6 in =2 in

.25 x 2 = .5 lb

answer: i think it is (1,-2)