Given that a ball is tossed from a 100 foot building upward with an initial velocity of 20 feet per second, the equation to model the situation is h(t)=−16t^2+20t+100 Answer the questions to follow, rounding to the nearest tenth. how high will the ball reach?

when will it hit the ground

Let y be the height above the ground for the ball. We can then write the equation as

y = -16t2 -22t + 130

If t = 0, then y = 130 feet as we are told.

We want to know when the ball strikes the ground, or when y = 0. So, set y = 0 and solve the quadratic for t.

-16t2 -22t + 130 = 0

We can divide the equation through by -2 to get

8t2 + 11t - 65 = 0

Unfortunately, there is no easy way to factor this equation. We go to the quadratic formula.

t = [-11 +/- [112 - 4(8)(-65)]1/2}/{(2)(8)}

We can simplify this as

t = [-11 +/- √2201]/16

√2201 > 11, so we only keep the positive root, since time must be positive.

So,

t = [-11 + √2201]/16 = 2.244 sec

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above