Sharon kicks a ball from the ground into the air with an upward velocity of 64 feet per second. The function h = -16t2 + 64t models the height h, in feet, of the ball at time t, in seconds. When will the ball reach the ground again? 1 second after the ball is thrown

2 seconds after the ball is thrown

3 seconds after the ball is thrown

4 seconds after the ball is thrown

i believe that the answer is 4 seconds but i dont understand how to work it out

Step-by-step explanation:

use the equation of motion for a projectile moving un der gravity h = ut + (1/2)gt^2 where u = initial velocity, h = height, t = time and g = acceleration due to gravvity here u = 64 fts-1 and g = -32 ft s-2

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068