A) The sixth term of an AP is twice the 3rd term and the first term is 3. Find the common difference and the 10th term

Step-by-step explanation:

The nth term of an AP is expressed as;

Tn = a+(n-1)d

a is the first term

n is the number of terms

d is the common difference

Sixth term

T6 = a+(6-1)d

T6 = a+5d

Third term;

T3 = a+(3-1)d

T3 = a+2d

If the sixth term of an AP is twice the 3rd term, then

a+5d = 2(a+2d)

a+5d = 2a+4d

Given a = 3

3+5d = 2(3)+4d

5d-4d = 6-3

d = 3

Common difference is 3

For the 10th term

T10 = a+9d

T10 = 3+9(3)

T10 = 3+27

T10 = 30

Hence the tenth term is 30

answer: i guess 105 degrees?

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)