Find the points where the graphs of y=1-x and y=x-3 intersect algebraically

The point of intersection is (2, -1).

Step-by-step explanation:

At the point of intersection both equations have same value of x and y.

y = x - 3

y = 1 - x

Since the 2 right sides are both = y:

x - 3 = 1 - x

x + x = 1 + 3

2x = 4

x = 2.

Substituting for x in equation 1:

y = 2 - 3 = -1.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

35 is an outlier

step-by-step explanation: