A set of 4 consecutive odd integers has a sum of 216. What are the integers?

Hope this helps!!

Step-by-step explanation:

So the four consecutive odd integers are: 51 , 53 , 55 and 57 .

If the first integer is n, then the other three are n+2,n+4 and n+6

and we have:

216=n+(n+2)+(n+4)+(n+6)=4n+12

Subtract 12 from both ends and transpose to get:

4n=204

Divide both sides by 4

to get:

n=51

So the four consecutive odd integers are:

51,53, 55 and 57.

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: