Find the cos sin and tan of 28 degrees in terms of the variables x, y, and k.

Step-by-step explanation:

For this problem, k is the hypotenuse, x is the side adjacent to 28, and y is the side opposite 28.

I would remember SOH CAH TOA.

S - Sine

O - Opposite

H - Hypotenuse

For this, it shows that the sine of the angle is opposite over hypotenuse. Therefore, y/k.

C - Cosine

A - Adjacent

H - Hypotenuse

For this, it shows that the cosine of the angle is adjacent over hypotenuse. Therefore, x/k

T - Tangent

O - Opposite

A - Adjacent

For this, it shows that the tangent of the angle is opposite over adjacent. Therefore, y/x

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11