Suppose the first coil of wire illustrated in the simulation is wound around the iron core 6 times. Suppose the second coil is wound around the core N2 = 12 times. Shortly after the switch has been closed, the flux through the second coil of wire changes from 1.9 Wb per turn to 2.4 Wb in each turn of wire over a time interval of 0.2 s. Find the magnitude of the emf induced in the coil.

30 V

Step-by-step explanation:

The induced emf, ε = -ΔΦ/Δt where  ΔΦ = change in magnetic flux and  Δt = time interval for change in flux.

Since we have N₂ = number of turns on second coil = 12 and initial flux per turn = 1.9 Wb per turn. The total initial flux per turn Φ₁ = 12 turns × 1.9 Wb per turn =  22.8 Wb.

Also, since we have N₂ = number of turns on second coil = 12 and final flux per turn = 2.4 Wb per turn. The total initial flux per turn Φ₂ = 12 turns × 2.4 Wb per turn =  28.8 Wb.

Since  Δt = 0.2 s and the magnitude of the induced emf in the second coil, ε = ΔΦ/Δt

= (Φ₂ - Φ₁)/Δt

= (28.8 Wb - 22.8 Wb)/0.2 s

= 6.0 Wb/0.2 s

= 30 V

the answer is 200

step-by-step explanation:

the way the question is worded, it seems to imply the $264 interest is simple interest, not compound interest.

the simple interest for 2 years is $264; the simple interest for 1 year is $132.

$132 interest on a $600 investment means an interest rate of (132/600)*100 = 22%.

the value of $200 at 22% interest compounded annually for three years is

200%281.22%29%5e3

the amount of interest is that value, minus the original $200.

based on context clues you gave i'm assuming the answer would be c.