In AABC shown below, L is the midpoint of BC, M is the midpoint of AB, and N is the midpoint of AC. If MN = 8, ML = 5, and NL = 6, find the perimeter of trapezoid BMNC.
Need help ASAP pls

the perimeter of trapezoid BMNC is 35

Given :

In  triangle ABC shown below, L is the midpoint of BC, M is the midpoint of AB, and N is the midpoint of AC. If MN = 8, ML = 5, and NL = 6

By midpoint theorem ,

M is the midpoint of AB, AB= 2 times NL

BM=NL

BM=6

N is the midpoint of AC

AC is 2 times of ML

NC=ML

NC=5

Perimeter of trapezoid is  sum of all the sides

Perimeter of BMNC = BM+MN+NC+CB

Perimeter =

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Step-by-step explanation:

see attached image.

perimeter of trapezoid = sides (6 + 8 + 5 + 8 + 8)

                                     = 35

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

what?

step-by-step explanation:

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