Question on picture attached, easy but i’m stuck (need help asap)

∠CDF = 54

Step-by-step explanation:

In ΔAEB,

AE ≅ AB

∠ABE = ∠E  = x   {Angles opposite to equal sides are equal}

∠EAB + ∠E +∠ABE = 180  {angle sum property of triangle}

  26  + x + x  = 180

      26 + 2x = 180

              2x = 180 - 26

             2x = 154

               x = 154/2

x = 77

∠ABE = ∠E = 77

In quadrilateral AECF

∠A + ∠E + ∠C + ∠F = 360

90 + 77 + ∠C  + 90 = 360

                ∠C + 257 = 360

                        ∠C = 360 - 257

    ∠C = 103

∠FCD + ∠BCD  = ∠C

∠FCD +  67 =  103

        ∠FCD = 103 - 67

        ∠FCD  = 36

ΔFCD,

∠FCD + ∠CDF + ∠CFD = 180

36 + ∠CDF + 90 = 180

       ∠CDF + 126 = 180

                   ∠CDF = 180 - 126

                  ∠CDF = 54

51

step-by-step explanation:

73-22=51 the   mass number minus the amount of protons gives you the amount of neutrons

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier