Find the domain of the relation {(0, 0), (1, 1), (2, 0)). Then determine whether the relation is a function.

A relation may or  may not be a function.

The relation is given as:

List out the x-values

The above set means that the x-values starts from 0 and ends at 2.

Hence, the domain is: [0,2]

For a relation to be a function, all y-values of the relation must point to different x-values.

So, we can say that, the given relation is a function, because all y-values have unique x values

Read more about relations and functions at:

link

Domain: 0,1,2

The relation is a Function.

Step-by-step explanation:

hope this helps

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: