scrie toti multiplii de trei cifre distincte ai numarului 5, care se pot forma cu cifrele: a) 5, 7 si 8; b) 0, 3 si 5. repede va roggg

I will answer in English.

Here, we want to find all the 3-digit multiples of 5, that can be formed with the digits:

a) 5, 7, and 8. (i suppose that we can not repeat the digits)

First, we know that all the multiples of 5 end with a 5 or a 0, then the possible ones here are:

875

785

(the five must always be at the end)

b) 0, 3, and 5.

Now we have two options, if the 5 is at the end, we have:

305

(035 is not an option, because is a 2-digit number).

if 0 is at the end, we have:

350

530

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

72 is the answer to this problem