Pls can someone help me factorise: 4u²‐u-3

(u - 1)(4u + 3)

Step-by-step explanation:

Given

4u² - u - 3

Consider the factors of the product of the coefficient of the u² term and the constant term which sum to give the coefficient of the u- term.

product = 4 × - 3 = - 12 and sum = - 1

The factors are -  4 and + 3

Use these factors to split the u- term

4u² - 4u + 3u - 3 ( factor the first/second and third/fourth terms )

= 4u(u - 1) + 3(u - 1) ← factor out (u - 1) from each term

= (u - 1)(4u + 3)

Thus

4u² - u - 3 = (u - 1)(4u + 3) ← in factored form

answer: asdfghjkl,mnbv

step-by-step explanation: