When a natural number is multiplied by itself. The result is called a perfect square. Since 1x1 = 1, 2x2=4, 3x3=9 and so on, then the numbers 1,4,9 etc are perfect squares. Using this knowledge work out which year in the 18th century (the years 1701 through to 1800) was a perfect square?

the answe i =−n+5

439400

step-by-step explanation:

130^2 = 16900

16900*26 = 439400

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

b. x- 48 =120

step-by-step explanation: