If 12 g of a radioactive substance are present initially and eight years later only 6 g remain, how much of the substance will be present after 11 years

4.083g

Step-by-step explanation:

12 g of a radioactive substance are present initially and eight years later only 6 g remain, how much of the substance will be present after 11 years

Starting with half life, we want to find k.

In a 4 year period, t=8 and A quantity will be reduced to (1/2)*A.

(1/2)= e^k8

In(1/2)

this is false ^.^ lol

3

step-by-step explanation:

divide 13.5 by 9 to get the scale factor. it equals 1.5

2 * 1.5 = 3