What mass of iron(III) chloride contains 4.13 x 10^23 chloride ions?

iron (III) chloride's chemical formula is FeCl₃  Since Fe (III) is Fe³⁺ and Cl is Cl⁻.  Given that, you know that 3 moles of Cl⁻ combine with 1 mole of FeCl₃.  

First, you need to find the number of moles of Cl⁻ is contained in  2.35x10^23 atoms of Cl⁻.  To do this you need to divide the number of Cl⁻ atoms by Avogadro's number (6.02x10^23atoms/mol) to get 0.3902 moles of Cl⁻.  Then you multiply 0.3902 by 1/3 (using the fact that there is 1mol Fe³⁺ per 3mol Cl⁻) to get the number of moles of FeCl₃ which is 0.1301mol FeCl₃.  Then to find the mass FeCl₃, you need to multiply the number of moles of FeCl₃ (which is 0.1301mol) by the molar mass of FeCl₃ (which is 162.15g/mol) to get 21.09g FeCl₃.

therefore the amount of FeCl₃ is 21.09g FeCl₃.

Step-by-step explanation:

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: