. A drag racing car’s engine produces 12,000 Newtons of thrust, pushing the car forward down the track. Frictional forces resist the forward motion of the car with a total backward force of 2010 Newtons. If the mass of the car is 820 kg, what is the acceleration of the vehicle? Round your answer to the nearest tenth.

14.6 meters per second per second
12.2 meters per second per second
17.1 meters per second per second
2.45 meters per second per second

answer is x<

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9

step-by-step explanation:

classify each pair of angles as alternate interior, same-side interior, or corresponding angles.