Motocross The path that a motocross dirt bike rider follows during a jump is given by y = -0.4x² + 4x + 10 where x is the horizontal distance (in feet) from the edge
of the ramp and y is the height (in feet). What is the maximum height of the rider
during the jump?
20
18
16
14
12
Height (feet)
10
6
4
2
0 2 4 6 8 10 12
Horizantal distance feet)
My

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

2/3

step-by-step explanation:

the slope of a line is equal to the rise/run. in this case the line rises 2 units for every +3 units it moves

a

step-by-step explanation:

the answer is a

hey there! : )

4y < -4

we need to isolate y. we can do this by simply dividing both sides by 4.

4y ÷ 4 > -4 ÷ 4

simplify.

y > -1

5 - y > 0

once again, we need to isolate y, so we can start off by subtracting 5 from both sides.

5 - y - 5 > 0 - 5

simplify.

-y > -5

divide both sides by -1.

** remember that when dividing any side by a negative, you must switch the sign! **

-y ÷ -1 < -5 ÷ -1

simplify.

y < 5

~hope i ! ~