A drag racing car’s engine produces 12,000 Newtons of thrust, pushing the car forward down the track. Frictional forces resist the forward motion of the car with a total backward force of 2010 Newtons. If the mass of the car is 820 kg, what is the acceleration of the vehicle? Round your answer to the nearest tenth. 2.45 meters per second per second
17.1 meters per second per second
12.2 meters per second per second
14.6 meters per second per second

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

step-by-step explanation:

it will be a cylinder. with a diameter of 8 and 4 single pieces high

c.

step-by-step explanation:

simple you would first have to get   a negative number where as 1 to be multiplied by 24 and then you would have to multiply 6 time 4 and then repeat that process until you reach your term